import fl.motion.Color;

var ar = new Array(11);

for (var i:Number = 0; i <= 10; i++) {
   ar[i] = this.addChild(new colorExperiment());
   ar[i].x = 25 * i;
}

var c:Color = new Color();
c.setTint(0x0000FF, 1);

var c2:Color = new Color();
c2.setTint(0xFF0000, 1);

ar[0].transform.colorTransform = c;

ar[10].transform.colorTransform = c2;

---------------------------------------------------------------------------
   *** Below here is what we did in class on Wednesday, March 12th ***
---------------------------------------------------------------------------

import fl.motion.Color;

var ar = new Array(11);

for (var j:Number = 0; j <= 10; j++) {

   ar[j] = this.addChild(new colorExperiment());
   ar[j].x = 25 * j;

}

var c:Color = new Color();
c.setTint(0x0000FF, 1);

var c2:Color = new Color();
c2.setTint(0xFF0000, 1);

ar[0].transform.colorTransform = c;

ar[10].transform.colorTransform = c2;

for (var i:Number = 1; i <= 9; i++) {

   var newColor:uint;
   newColor = Color.interpolateColor(0x0000FF, 0xFF0000, i / 10);

   c.setTint(newColor, 1);
   ar[i].transform.colorTransform = c;

   trace(newColor.toString(16));
}

/* Here are the colors that interpolateColor() method of the Color class
   came up with on the gradient from RED to BLUE, from

   0x0000FF to 0xFF0000    
         --      --

         --      --
   0x0000FF to 0xFF0000    
     RRGGBB      RRGGBB         RR = red            RGB graphics
         --      --             GG = green 
                                BB = blue

              FF   = 255  = 11111111
                16      10          2

              FF is base 16, hexadecimal, thus the 0x in front of the
                               -                    -    RRGGBB digits.

              255 is base ten or decimal.

              11111111 is base two or binary.

   Here are the 9 colors between perfect BLUE and perfect RED.

1900E5        <---- mostly BLUE (E5) with a little bit of RED (19)
3300CC
4C00B2
660099
7F007F        <---- RED = 7F = BLUE = 7F  (Note 7F is 127 and FF is 255)
990066
B2004C                                     255
CC0032                                    ----- = 127.5
E50019                                      2
 
        Finally, the last entry is mostly RED and a little bit of BLUE.
                                          E5                      19

        Notice how the colors are mirror images of each other too!

0000FF
        1900e5
                3300cc
                       4c00b2
                               660099
                                       7f007f
                               990066
                       b2004c
                cc0032
        e50019
FF0000