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> int[] msg = { 78, 111, 119, 32, 72, 105, 114, 105, 110, 103 };
> for ( int ch : msg )
      System.out.print( (char) ch );
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> {
for ( int ch : msg )
  System.out.print( (char) ch );
System.out.println();
}
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============================== Look at Homework 1...

============================== recall our method to lighten an image

  public void lighter( double amount )
  {
    Pixel[] pixels = this.getPixels();
    for ( int i = 0; i < pixels.length; i++ )
    {
      Pixel p = pixels[i];
      double factor = 1 + amount;

      p.setRed  ( (int) (p.getRed  () * factor) );
      p.setGreen( (int) (p.getGreen() * factor) );
      p.setBlue ( (int) (p.getBlue () * factor) );
    }
  }

> Picture p = new Picture( "/Users/wallingf/Desktop/billy-joel-sf.jpg" );
> p.show();
> p.lighter( 0.1 );
> p.repaint();
> p.lighter( 0.4 );
> p.repaint();
> p = new Picture( "/Users/wallingf/Desktop/greece.jpg" );
> p.show();
> p.lighter( 0.5 );
> p.repaint();

// NOW: step through for loop


============================== EXERCISE: write a loop over an array of doubles

> double[] mileageForWeek = {3, 8, 10, 7, 10, 0, 20};

> double sum = 0;
> for (int i = 0; i < mileageForWeek.length; i++)
    sum = sum + mileageForWeek[i];

> sum
58.0

> sum / mileageForWeek.length
8.285714285714286

> sum / 6
9.666666666666666

// BONUS QUESTION:  How would I find the average run if I didn't know
//                  how many rest days I had?  [Loop to count non-0 days!]



====================== pixel operations that depend on location: nested loops

// Look at Delbert T. Quimby.

> Picture quimby;
> quimby = new Picture( "/Users/wallingf/Desktop/delbert-t-quimby.jpg" );
> quimby.show();


// I'd like to doctor the image so that it has a bookcase
// across the entire background.

> int width = quimby.getWidth(); width
400

// First, explore with PictureExplorer...
> PictureExplorer explorer = new PictureExplorer( quimby );

// Find (393, 184) as bottom of bookcase on right.
// Decide to copy right half of image, down to y = 184,
// into left half, column by column.